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4x^2+61x+204=0
a = 4; b = 61; c = +204;
Δ = b2-4ac
Δ = 612-4·4·204
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{457}}{2*4}=\frac{-61-\sqrt{457}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{457}}{2*4}=\frac{-61+\sqrt{457}}{8} $
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